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A 2 B has antifluorite structure ( B forms FCC lattice and A occupies tetrahedral voids). If all ions along any one body diagonal are removed, then new formula of compound will be:

Options

  1. AA 4 B 5
  2. BA 8 B 5
  3. CA 7 B 6
  4. DA 8 B 4

Correct answer

B. A 8 B 5

Step-by-step solution

On one body diagonal, 2   A -atoms(full contribution) 2   B -atoms 1 8 c o n t r i b u t i o n s lie. So, new formula = A 8 - 2 B 4 - 1 4 = A 8 B 5

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