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NTA Abhyas 2020
Exam
NTA Abhyas
Year
2020
Subject
Chemistry
Chapter
Solid State

NTA Abhyas 2020 · Chemistry · Solid State

A _ 2 B has antifluorite structure ( B forms FCC lattice and A...

A2B{A}_{2}B has antifluorite structure (B\text{B} forms FCC\text{FCC} lattice and A\text{A} occupies tetrahedral voids). If all ions along any one body diagonal are removed, then new formula of compound will be:

Options

  1. AA4B5{A}_{4} {B}_{5}
  2. BA8B5{A}_{8} {B}_{5}
  3. CA7B6{A}_{7} {B}_{6}
  4. DA8B4{A}_{8} {B}_{4}

Correct answer

B. A8B5{A}_{8} {B}_{5}

Step-by-step solution

On one body diagonal, 2A\text{2}\text{A}-atoms(full contribution) 2B\text{2}\text{B}-atoms (18contributions)\left(\dfrac{1}{8}contributions\right) lie. So, new formula = A8−2B4−14=A8B5{A}_{8 - 2}{B}_{4 - \dfrac{1}{4}} = {A}_{8}{B}_{5}
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