NTA Abhyas JEE Main2020ChemistrySolid StatePractice
T l A l S O 4 2 . x H 2 O is bcc with edge length ‘ a ’ = 1.22 n m . If the density of the solid is 2.32 g / c c , then the value of x is (Given: N A = 6 × 10 23 , atomtextc weight (in g/mol ) TI = 204, Al = 27, S = 32, O = 16, H = 1 )
Options
- A2
- B4
- C47
- D70
Correct answer
C. 47
Step-by-step solution
For any unit cell d   =   2   M a 3   N A (for BCC,   Z   =   2 ) 2.32 = 2 × M 6 × 1 0 23 × 1.22 3 × 1 0 – 21 ∴ M = 1264 So 4 2 3 + x 1 8 = 1 2 6 4 x = 4 7