NTA Abhyas JEE Main2020ChemistrySolid StatePractice
The arrangement of X - ions around A + ion in solid AX is given in the figure (not drawn to scale). If the radius of X - is 250 pm , the radius of A + is
Options
- A104 pm
- B125 pm
- C183 pm
- D57 pm
Correct answer
A. 104 pm
Step-by-step solution
r A + r x - = 0.414 = r A + 250 r A + = 0 . 414 × 25 0 pm = 10 4 pm