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NTA Abhyas 2020
Exam
NTA Abhyas
Year
2020
Subject
Chemistry
Chapter
Solid State

NTA Abhyas 2020 · Chemistry · Solid State

The arrangement of X^ - ions around A^ + ion in solid AX is given...

The arrangement of X−X^{-} ions around A+A^{+} ion in solid AX\text{AX} is given in the figure (not drawn to scale). If the radius of X−X^{-} is 250pm\text{250}\text{pm}, the radius of A+A^{+} is

The arrangement of X^ - ions around A^ + ion in solid AX is given in the figure (not drawn to scale). If the radius of

Options

  1. A104 pm
  2. B125 pm
  3. C183 pm
  4. D57 pm

Correct answer

A. 104 pm

Step-by-step solution

rA+rx−=0.414=rA+250\dfrac{{r}_A^{+}}{{r}_x^{-}} = 0.414 = \dfrac{{r}_A^{+}}{250}
rA+=0.414×250pm=104pm{r}_A^{+} = 0 . \text{414} \times \text{25}0\text{pm} = 10\text{4}\text{pm}
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