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NTA Abhyas 2020
Exam
NTA Abhyas
Year
2020
Subject
Chemistry
Chapter
Solid State

NTA Abhyas 2020 · Chemistry · Solid State

The number of unit cells present in 1 g cube shaped ideal crystal...

The number of unit cells present in 1 g cube shaped ideal crystal of solid A+B−A^{+}B^{-} (with CCP close packing) (formula mass =60= 60 ) are

Options

  1. A2.5×10212.5 \times 1{0}^{21}
  2. B6.02×10236.02 \times 1{0}^{23}
  3. C4.0×10224.0 \times 1{0}^{22}
  4. D1.0×10221.0 \times 1{0}^{22}

Correct answer

A. 2.5×10212.5 \times 1{0}^{21}

Step-by-step solution

Number of moles present in 1g=1601g = \dfrac{1}{60}

So number of formula units in 160\dfrac{1}{60} moles

=160×6.023×1023=1022=10×1021= \dfrac{1}{60} \times 6.023 \times 1{0}^{23} = 1{0}^{22} = 10 \times 1{0}^{21}

Since 4 formula units constitute a unit cell

So number of unit cells present

=104×1021=2.5×1021= \dfrac{10}{4} \times 1{0}^{21} = 2.5 \times 1{0}^{21}
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