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Edge length of face centred cubic unit cell of an ionic solid AB is 508 pm. If the radius of A + ion is 110 pm, the radius of B - ion in pm will be

Correct answer

144

Step-by-step solution

Edge length = 2 r A + + 2 r B - 508 = 2 × 110 + 2 r B - 2 r B - = 508 - 220 = 288 r B - = 144 pm

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