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The volume of atoms ( r a d i u s r ) present in fcc unit cell of metal is :

Options

  1. A20 3 π r 3
  2. B24 3 π r 3
  3. C12 3 π r 3
  4. D16 3 π r 3

Correct answer

D. 16 3 π r 3

Step-by-step solution

Volume of atom in a cell = 4 3 πr 3 × N N = 4 for fcc = 4 3 × π r 3 × 4 = 16 3 π r 3

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