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1 .84 g mixture of CaCO 3 and MgCO 3 when heated to constant weight of 0 .96 g as residue. Find the mass of CaCO 3 (in grams) in the mixture. M CaCO 3 = 100 g/mole, M MgCO 3 = 84 g/mole

Correct answer

1.00

Step-by-step solution

MgCO 3 + CaCO 3 ⟶ MgO + CaO + 2 CO 2 g 1. 8 4 - x g x g 0. 8 8 g Moles 1 · 8 4 - x 8 4 x 1 0 0 0 · 8 8 4 4 ------------------------------------------------------------------------------------- Apply POAC to C 1. 8 4 - x 8 4 × 1 + x 1 0 0 × 1 = 0. 8 8 4 4 × 1 = 0. 0 2 1 8 4 - 1 0 0 x + 8 4 x = 1 6 8 ∴ 1 6 = 1 6 x ∴ x = 1 g

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