NTA Abhyas JEE Main2020ChemistrySome Basic Concepts of ChemistryPractice
Calculate the minimum mass of C l 2 in grams required to produce 37 .25 g KCl? C l 2 + 2 K O H → K C l + K C l O + H 2 O
Correct answer
35.5
Step-by-step solution
C l 2 + 2 K O H → K C l + K C l O + H 2 O 37 .25   g 37.25 74.5 m o l 0.5 m o l K C l Mole of C l 2 required = 0 .5   mol Mass of C l 2 required = 0.5 × 71 = 35.5 g