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NaCl O 3 is used in spacecraft to produce O 2 . The daily consumption of pure O 2 by a person is 492 L at 1 atm, 300 K . How much amount of NaCl O 3 (in grams) is required to produce O 2 for the daily consumption of a person at 1 atm, 300 K? NaCl O 3 s + Fe s → O 2 g + NaCl s + FeO s R = 0.0 82 L atm mo l – 1 K – 1

Options

  1. A21.3
  2. B1115
  3. C2130
  4. D4260

Correct answer

C. 2130

Step-by-step solution

Moles of NaCl O 3 = moles of O 2 moles of O 2 = PV RT = 1 × 492 0.082 × 300 = 20 moles As molecular mass of NaCl O 3 = 106.5 NaCl O 3 = 20 × 106.5 = 213 0 g

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