NTA Abhyas JEE Main2020ChemistrySome Basic Concepts of ChemistryPractice
Aluminum carbide A l 4 C 3 liberates methane on treatment with water. The grams of aluminum carbide required to produce 11 .2 L of methane under STP conditions is [Given Al = 27 ]
Options
- A48
- B72
- C144
- D24
Correct answer
D. 24
Step-by-step solution
A l 4 C 3 + 12 H 2 O → 3 C H 4 + 4 A l O H 3 So 67 .2 L C H 4 evolved by 144 g A l 4 C 3 11 .2 L C H 4 will be evolved = 144 67.2 × 11.2 = 24 g