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At 100 o C and 1 atm. if the density of liquid water is 1.0 gc m - 3 and that of water vapour is 0.0006 gc m - 3 , then the volume occupied by water molecules in 1 litre of steam at that temperature

Options

  1. A6 c m 3
  2. B60 c m 3
  3. C0.6 c m 3
  4. D0.06 c m 3

Correct answer

C. 0.6 c m 3

Step-by-step solution

1L = 1000 mL = 1000 c m 3 mass = density × volume = ( 0.000 6 g c m - 3 ) × ( 1000 c m 3 ) = 0 . 6g As 18 g of water = 18 c m 3 So 0.6 g of water = 0 . 6 c m 3 Hence actual volume occupied by molecules = 0 . 6 c m 3

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