NTA Abhyas JEE Main2020ChemistrySome Basic Concepts of ChemistryPractice
2.76 g of silver carbonate on being strongly heated yields a residue weighing
Options
- A2.16 g
- B2.48 g
- C2.32 g
- D2.64 g
Correct answer
A. 2.16 g
Step-by-step solution
A g 2 C O 3 2.76 → Δ A g 2 O + C O 2 → Δ 2 A g + 1 2 O 2 r e s i d u e Note: A g 2 O is thermally unstable and decompose on heating liberating oxygen. Molecular weight of A g 2 C O 3 = 108 × 2 + 12 + 16 × 3 = 276 g So 276 g of A g 2 C O 3 on heating gives residue = 2 × 108 = 216 g of Ag So 2.76 of A g 2 C O 3 on heating gives = 216 276 × 2.76 = 2.16 g of Ag