Zinc and hydrochloric acid react according to the following reaction : Z n s + 2 H C l a q . → Z n C l 2 ( a q . ) + H 2 ( g ) If 0.30 m o l e o f Zn is added to 0.52 m o l e HCl, how many moles of H 2 is produced?

Step-by-step solution

∵ M o l e r a t i o o f Z n : H C l : H 2 i s 1 : 2 : 1 2 mole HCl gives = 1 mole H 2 0.52 mole HCl gives = 1 × 0.52 2 = 0.26 mole Note that H C l is used completely and thus it is limiting reagent.