What volume of hydrogen in ml will be liberated at STP by the reaction of Zn on 50 ml of dilute H 2 S O 4 of specific gravity 1.3 having purity of 40%? Report your answer by rounding it upto nearest whole number.

Step-by-step solution

Mass of H 2 S O 4 = 50 × 13 × 40 100 = 26 g Z n + H 2 S O 4 98 g o r 1 mole → Z n S O 4 - + H 2 22.4 L a t NTP As 98 gm H 2 S O 4 provides = 22.4 L H 2 So 26 gm H 2 S O 4 provides = 22.4 × 26 98 = 5.95 L ≈ 6 L