NTA Abhyas JEE Main2020ChemistrySome Basic Concepts of ChemistryPractice
A 10.0 g sample of a mixture of calcium chloride and sodium chloride is treated with N a 2 C O 3 to precipitate the calcium as calcium carbonate. This C a C O 3 is heated to convert all the calcium to CaO and the final mass of CaO is 1.62 gms. The % by mass of C a C l 2 in the original mixture is
Options
- A15.2%
- B32.1%
- C21.8%
- D11.07%
Correct answer
B. 32.1%
Step-by-step solution
Moles = Weight in gm Molecular weight Moles of CaO = 1 .62 56 Moles of C a C l 2 = 1.62 56 Mass of CaCl 2 = 1 .62 56 × 111 = 3 .21 gm Mass %   =   Weight   in   gm Total   weight   given   ×   100 % of C a C l 2 = 3.21 10 × 100 = 32.1 %