NTA Abhyas JEE Main2020ChemistrySome Basic Concepts of ChemistryPractice
0.7 grams of N a 2 C O 3 . x H 2 O were dissolved in water and the volume was made to 100 mL, 20 mL of this solution required 19.8 mL of N/10 HCl for complete neutralization. The value of x is Report your answer by rounding it upto nearest whole number.
Correct answer
2
Step-by-step solution
Meq. of Na 2 CO 3 ⋅ xH 2 O in 20 mL=19 .8× 1 10 ∴ Meq. of Na 2 CO 3 ⋅ xH 2 O Na 2 CO 3 ⋅ xH 2 O in 100 mL = 19.8 × 1 10 × 5 ∴ w E × 1000 = 19.8 × 1 10 × 5 or 0.7 M 2 × 1000 = 19.8 2 ∴ M = 141.4 1 23 × 2 + 12 + 3 × 16 + 18 x = 141.4 1 ∴   x ≅ 2