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What weight of H 2 C 2 O 4 . 2 H 2 O (molecular weight = 126 g/mol) should be dissolved to prepare 250 ml of centinormal solution to be used as reducing agent?

Options

  1. A0.635 g
  2. B0.1575 g
  3. C0.1263 g
  4. D0.835 g

Correct answer

B. 0.1575 g

Step-by-step solution

For mole of given acid C 2 O 4 2 - present = 1 mole So C 2 O 4 2 - → C O 2 + 2 e - So n-factor for H 2 C 2 O 4 . 2 H 2 O as a reducing agent = 2 Equivalent weight (E) = M 2 = 126 2 = 63 250 ml of centinormal solution (NV) = 250 100 × 1 0 - 3 equivalent So Weight of H 2 C 2 O 4 . 2 H 2 O required (W) = N V E = 250 100 × 1 0 - 3 × 63 = 0 . 1575 g

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