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Which of the following gives the molarity of a 17.0% by mass solution of sodium acetate, CH 3 COONa FM = 82 .0 amu in water? Given the density is 1 .09 g/mol .

Options

  1. A2.26 × 1 0 - 6 M
  2. B0.207 M
  3. C2.07 M
  4. D2.26 M

Correct answer

D. 2.26 M

Step-by-step solution

17 .0% solution of CH 3 COONa means that 100 g solution contain 17 g of CH 3 COONa . Moles of CH 3 COONa = 17 g 82 .0 g mol − 1 = 17 82 .0 mol Volume of 100 g solution = Mass of solution Density of solution = 100 g 1 .09 g mol − 1 = 100 1 .09 mL So molarity of solution = Moles of solute Liter of soln . =   17 82 .0 mol 100 1 .09 ×10 − 3   L =   2 .259   M   =   2 .26   M

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