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At STP, 2.8 litres of hydrogen sulphide were mixed with 1.6 litres of sulphur dioxide and the reaction occurred according to the equation 2 H 2 S g + S O 2 g → 2 H 2 O l + 3 S s Which of the following shows the volume of the gas remaining after the reaction?

Options

  1. A0.2 litres of S O 2 g
  2. B0.4 litres of H 2 g
  3. C1.2 litres of H 2 S g
  4. D1.2 litres of S O 2 g

Correct answer

A. 0.2 litres of S O 2 g

Step-by-step solution

So, Sol 2 vol H 2 S ≡ 1 vol SO 2 or 2 .8 L H 2 S = 1 .4 L SO 2 Hence, after reaction, volume of remaining S O 2 = 1.6 − 1.4 L = 0.2 L

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