On subjecting 10 ml mixture of N 2 and CO to repeated electric spark to form CO 2 and NO, 7 ml of O 2 was required for combustion. What was the mole percent of CO in the mixture ? (All volumes were measured under identical conditions)

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Correct answer: D. 60

N 2 + O 2 → 2 NO CO + 1 2 O 2 → CO 2 Let x ml be the volume of N 2 in 10 ml mixture. Total Volume of O 2 required = x + 1 0 - x 2 = 7 (given) ⇒ x = 4 ml Volume of CO = 1 0 - 4 = 6 ml Mol % of CO = 6 × 1 0 0 1 0 = 6 0

On subjecting 10 ml mixture of N 2 and CO to repeated electric spark to form CO 2 and NO, 7 ml of O 2 was required for combustion. What was the mole percent of CO in the mixture ? (All volumes were measured under identical conditions)

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