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NTA Abhyas JEE Main2020ChemistrySome Basic Concepts of ChemistryPractice

A sample of a hydrate of barium chloride weighing 61 g was heated until all the water of hydration is removed. The dried sample weighed 52 g. The formula of the hydrated salt is: (atomic mass, Ba = 137 amu, Cl = 35.5 amu)

Options

  1. AB a C l 2 ⋅ H 2 O
  2. BB a C l 2 ⋅ 3 H 2 O
  3. CB a C l 2 ⋅ 4 H 2 O
  4. DB a C l 2 ⋅ 2 H 2 O

Correct answer

D. B a C l 2 ⋅ 2 H 2 O

Step-by-step solution

B a C l 2 ⋅ x H 2 O → B a C l 2 + x H 2 O ( 137 + 2 × 35.5 + 18 x ) = 208 + 18 x g/mole 208 + 18 x 208 = 61 52 10816 + 936 x = 12688 936 x = 1872 x = 2 Formula is B a C l 2 ⋅ 2 H 2 O

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