NTA Abhyas JEE Main2020ChemistrySome Basic Concepts of ChemistryPractice

How many mL of 22.4 volume H 2 O 2 is required to oxidise 0.1 mol of H 2 S gas to S?

Correct answer

Step-by-step solution

H 2 O 2 1 mol + H 2 S 1 mol → 2 H 2 O + S 0.1 mol H 2 S require H 2 O 2 = 0.1 mol Molarity of 22.4 volume H 2 O 2 = 22.4 11.2 = 2 M Now volume of H 2 O 2 required = m o l m o l a r i t y = 0.1 2 L = 0.1   ×   1000 2   = 50   mL

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