NTA Abhyas JEE Main2020ChemistrySome Basic Concepts of ChemistryPractice
a g K H C 2 O 4 is used to neutralize 100 mL of 0.02M K M n O 4 in acid medium, where as b g K H C 2 O 4 is used to neutralize 100 mL of 0.02M C a ( O H ) 2 then,
Options
- Aa = b
- B4 a = 5 b
- C5 a = 4 b
- D2 a = b
Correct answer
B. 4 a = 5 b
Step-by-step solution
milli eq . of KHC 2 O 4 = milli eq . of KMnO 4 ( C 3 + ) 2 → 2 C 4 + + 2 e M n 7 + + 5 e → M n 2 + a M 2 × 1000 = 100 × 0.02 × 5 a = 5 × 1 0 – 3 M milli eq . of KHC 2 O 4 = milli eq . of Ca(OH) 2 K H C 2 O 4 acts as acidic salt b M 1 × 1000 = 100 × 0.02 × 2 b = 4 × 1 0 – 3 M a b = 5 4