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What mass in miligram of C a C O 3 is required to react completely with 25 ml of 0.75 M HCl according to the reaction C a C O 3 ( s ) + 2 H C l ( a ) → C a C l 2 ( a ) + C O 2 ( g ) + H 2 O ( l ) ?

Correct answer

937.5

Step-by-step solution

Given CaCO 3 (s) + 2HCl (aq) → CaCl 2 (aq) + CO 2 (g) + H 2 O (l) Moles present in 25 ml of 0.75 M HCl = 0.75 1000 × 25 = 0.01875 moles Since 2 moles react completely with 1 mole CaCO 3 = 100 g 0.01875 moles react completely with CaCO 3 = 100 2 × 0.01875 0.9375 g = 937.5 mg

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