NTA Abhyas JEE Main2020ChemistryStates of MatterPractice
One mole of an ideal monoatomic gas is mixed with one mole of an ideal diatomic gas. The molar specific heat of the mixture at constant volume is (in Calories)
Correct answer
4.00
Step-by-step solution
C v,m = 3 2 R (for monoatomic gas) C v,m = 5 2 R (for diatomic gas) for the mixture, (C v,m ) mix = 3 2 R × 1 + 5 2 R × 1 1 + 1 = 2 R ∴ (C v,m ) mix = 4 cal