NTA Abhyas JEE Main2020ChemistryStates of MatterPractice
An open vessel at 27 o C is heated until 3/8 th of the air in it has been expelled. Assuming that the volume remains constant, calculate the temperature at which the vessel was heated
Options
- A307 o   C
- B107 o   C
- C480 o   C
- D207 o   C
Correct answer
D. 207 o   C
Step-by-step solution
If 3 t h 8 of the air is expelled out then remaining air = 5 8 In the open vessel volume and pressure are both constant but moles are decreasing ∴ n 1 T 1 = n 2 T 2 ∴ n 1 × 300 = 5 8 n 1 T 2 ∴ T 2 = 8 5 × T 1 = 8 5 × 300 = 480 K = 480 − 273 = 207 o C