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NTA Abhyas 2020
Exam
NTA Abhyas
Year
2020
Subject
Chemistry
Chapter
States of Matter

NTA Abhyas 2020 · Chemistry · States of Matter

One mole of a monoatomic real gas satisfies the equation p(V - b) =...

One mole of a monoatomic real gas satisfies the equation p(V−b)=RTp\left(V - b\right) = RT where b is a constant. The relationship of interatomic potential V(r)V ( r ) and interatomic distance r for the gas is given byOne mole of a monoatomic real gas satisfies the equation p(V - b) = RT where b is a constant. The relationship ofOne mole of a monoatomic real gas satisfies the equation p(V - b) = RT where b is a constant. The relationship ofOne mole of a monoatomic real gas satisfies the equation p(V - b) = RT where b is a constant. The relationship ofOne mole of a monoatomic real gas satisfies the equation p(V - b) = RT where b is a constant. The relationship of

Options

  1. AThe number of statement/s which are the characteristics of physisorption is ___________. A. It is highly specific in
  2. BThe number of statement/s which are the characteristics of physisorption is ___________. A. It is highly specific in
  3. CThe number of statement/s which are the characteristics of physisorption is ___________. A. It is highly specific in
  4. DThe number of statement/s which are the characteristics of physisorption is ___________. A. It is highly specific in

Correct answer

C. The number of statement/s which are the characteristics of physisorption is ___________. A. It is highly specific in

Step-by-step solution

Here the given equation is P(V−b)=RTP ( V - b ) = RT.
On comparing with van der Waals' equation
\left[P + \dfrac{a}{V^{2}}\right] [ V - b ] = RT<br/>Thatis<br />That isa = 0.
It means only repulsive forces are present which are contributive only at very close distance so the potential energy will increase abruptly. i.e., graph C is correct.
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