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One mole of N 2 O 4 (g) at 300 K is kept in a closed container under one atmosphere. It is heated to 600 K when 20% by mass of N 2 O 4 (g) decomposes to N O 2 (g). The resultant pressure (in atm) is

Correct answer

2.4

Step-by-step solution

N 2 O 4 1 1 - 0.2 ↔ 2N O 2 0 0.4 = 0.8 Number of moles at 300 K = 1 No. of moles at 600 K = 0.8 + 0.4 = 1.2 V is constant P 2 P 1 = n 2 T 2 n 1 T 1 P 2 1 = 1.2 × 600 1 × 300 = 2.4 a t m

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