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At 400 K, the root mean square (rms) speed of a gas X (molecular weight = 40) is equal to the most probable speed of gas Y at 60 K. The molecular weight of the gas Y is

Correct answer

4

Step-by-step solution

v r m s of X = 3 R T x M x ; v m p of Y = 2 R T y M y Given v r m s = v m p 3 R T x M x = 2 R T y M y M y = 2 R T y M x 3 R T x = 2 × 60 × 40 3 × 400 = 4

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