NTA Abhyas JEE Main2020MathematicsEllipsePractice
If the normal to the ellipse x 2 25 + y 2 1 = 1 is at a distance p from the origin, then the maximum value of p is
Correct answer
4
Step-by-step solution
Equation of the normal is 5 sec θ x - c o s e c θ y = 2 4 So, p = 24 25 sec 2 θ + c o s e c 2 θ = 24 36 + 5 tan θ - cot θ 2 p m a x = 24 6 = 4