NTA Abhyas 2020
- Exam
- NTA Abhyas
- Year
- 2020
- Subject
- Mathematics
- Chapter
- Ellipse
NTA Abhyas 2020 · Mathematics · Ellipse
The length of the minor axis of the ellipse (5x - 10) ^ 2 + (5y +...
The length of the minor axis of the ellipse ^{2} + {\left(5y + 15\right)}^{2} = \dfrac{{\left(3x - 4y + 7\right)}^{2}}{4} is
Options
- A units
- B units
- C units
- D units
Correct answer
D. units
Step-by-step solution
{\left(x - 2\right)}^{2} + {\left(y + 3\right)}^{2} = {\left(\dfrac{1}{2}\dfrac{3x - 4y + 7}{5}\right)}^{2} is an ellipse, whose focus is directix and eccentricity is
Length of from focus to directrix is
So, length of major axis is
and length of minor axis,~