NTA Abhyas JEE Main2020MathematicsEllipsePractice
If a , b ∈ R satisfy the equation a 2 + 4 b 2 - 4 = 0 , then the minimum value of 2 a + 3 b will be
Options
- A- 4
- B- 5
- C- 6
- D- 10
Correct answer
B. - 5
Step-by-step solution
Given equation is a 2 4 + b 2 = 1 Putting a = 2 cos ⁡ θ ,   b = sin ⁡ θ , we get, 2 a + 3 b = 2 2 cos ⁡ θ + 3 sin ⁡ θ = 4 cos θ + 3 sin θ ⇒ Minimum value = - 4 2 + 3 2 = - 5