NTA Abhyas JEE Main2020MathematicsLimitsPractice
The value of l i m x → 0 x c o t 4 x t a n 2 3 x c o t 2 6 x is equal to
Options
- A0
- B4
- C2 9
- D1
Correct answer
D. 1
Step-by-step solution
l i m x → 0 9 x 2 tan 3 x 2 1 9 x ⋅ tan 6 x 2 36 ⋅ x 2 ⋅ 4 x tan 4 x 36 x 2 4 x = 1 × 1 9 × 1 × 1 × 36 4 = 1