NTA Abhyas JEE Main2020MathematicsLimitsPractice
The value of l i m x → 0 1 - c o s 3 sin x sin x s i n sin x c o s sin x is equal to
Options
- A3 2
- B1
- C0
- D2
Correct answer
A. 3 2
Step-by-step solution
Let, sin ⁡ x = t ⇒ l i m t → 0   1 - c o s 3 t t sin ⁡ t cos ⁡ t ⇒ l i m t → 0 1 - cos ⁡ t t 2 × t sin ⁡ t × 1 + cos ⁡ t + cos 2 ⁡ t cos ⁡ t ⇒ 1 2 × 1 × 1 + 1 + 1 1 = 3 2