NTA Abhyas JEE Main2020MathematicsTrigonometric Ratios & IdentitiesPractice
If E = cos 2 71 o + cos 2 49 o + cos 71 o cos 49 o , then the value of 10 E is equal to
Options
- A7 . 5
- B2 . 5
- C12 . 5
- D10 . 5
Correct answer
A. 7 . 5
Step-by-step solution
E = 1 + cos 142 o 2 + 1 + cos 98 o 2 + 1 2 2 cos 71 o cos 49 o = 1 + 1 2 cos 142 o + cos 98 o + 1 2 cos 120 o + cos 22 o = 1 + 1 2 2 cos 120 o cos 22 o + 1 2 - 1 2 + cos 22 o = 1 + - 1 2 cos 22 o - 1 4 + 1 2 cos 22 o = 3 4 E = 3 4 = 0.75 ⇒ 10 E = 7.5