If& (2sin α)/(1 + cos α + sin α) = (3)/(4) , then the value of (1 -...

Let,& $x = \dfrac{2sin \alpha}{1 + cos \alpha + sin \alpha}$
Let, $y = \dfrac{1 - cos \alpha + sin \alpha}{1 + sin \alpha} .$

Now, $\dfrac{x}{y} = \dfrac{2sin \alpha\left(1 + sin \alpha\right)}{{\left(1 + sin \alpha\right)}^{2} - \cos^{2} \alpha}$
$⇒ \dfrac{x}{y} = \dfrac{2sin \alpha\left(1 + sin \alpha\right)}{1 + \sin^{2} \alpha + 2sin \alpha - 1 + \sin^{2} \alpha} = 1$
$⇒ x = y = \dfrac{3}{4}$