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NTA Abhyas 2020
Exam
NTA Abhyas
Year
2020
Subject
Physics
Chapter
Thermal Properties of Matter

NTA Abhyas 2020 · Physics · Thermal Properties of Matter

A body cools from 50 ° C to 40 ° C in 5 minutes. Its temperature...

A body cools from 50°C50 ° C to 40°C40 ° C in 55 minutes. Its temperature comes down to 33.33°C33. 33 ° C in the next 55 minutes. The temperature of the surroundings is

Options

  1. A15℃15 ℃
  2. B20℃20 ℃
  3. C25℃25 ℃
  4. D10℃10 ℃

Correct answer

B. 20℃20 ℃

Step-by-step solution

Using Newton's law of cooling,

logθ2−θ0θ1−θ0=−Kt\dfrac{{\theta}_{2} - {\theta}_{0}}{{\theta}_{1} - {\theta}_{0}} = - Kt

log 40−θ050−θ0=−K×5\dfrac{40 - {\theta}_{0}}{50 - {\theta}_{0}} = - K \times 5 .....(i)

log 33.33−θ040−θ0=−K×5\dfrac{33.33 - {\theta}_{0}}{40 - {\theta}_{0}} = - K \times 5 .....(ii)

From Eqs.(i) and (ii),

40−θ050−θ0=33.33−θ040−θ0\dfrac{40 - {\theta}_{0}}{50 - {\theta}_{0}} = \dfrac{33.33 - {\theta}_{0}}{40 - {\theta}_{0}}

On solving, we get

θ0=19.95℃≈20℃{\theta}_{0} = 19.95℃ \approx 20℃
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