The arm PQ of a rectangular conductor is moving from x = 0 to x = 2b outwards and then inwards from x = 2b to x = 0 as shown in the figure. A uniform magnetic field perpendicular to the plane is acting from x = 0 to x =

Question

Quantrex Academy · Accepted Answer

Correct answer: C. A —Flux, B — EMF , C —Power dissipated

As rod moves in field area increases upto

x = b

, then field is absent and again flux is generated on return journey from

x = b

to

x = 0

. Thus plot

A

for flux.

⇒ e = - \dfrac{dϕ}{dt} ⇒

curve

B

for

emf

⇒

Power dissipated

= vi ⇒

curve

C

for power dissipated

The arm PQ of a rectangular conductor is moving from x = 0 to x =...

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