A square loop of area A is moving out of the uniform magnetic field (B) with constant velocity v . The EMF (e) induced in the loop is

Step-by-step solution

Let the side length of the square loop be l . Since the area of the square loop is A , we have l^2 = A , which gives l = A . When the loop moves out of the uniform magnetic field with constant velocity v , the motional EMF induced across the side of length l perpendicular to the velocity is given by: e = Bvl Substituting the value of l , we get: e = Bv A Answer: Bv A