The value of mutual inductance of two coils is 6 mH. The current in one of the coil changes from 7 A to 2 A in 0.2 second, so that e.m.f. is induced in the other coil. If the resistance of the coil is 6\ , the value of

Question

Quantrex Academy · Accepted Answer

Correct answer: B. 5 mC

The induced emf in the secondary coil is given by

e = -M \dfrac{\Delta I}{\Delta t}

.

The induced current is

i = \dfrac{e}{R} = -\dfrac{M}{R} \dfrac{\Delta I}{\Delta t}

.

The induced charge passing through the coil is

q = i \Delta t = -\dfrac{M}{R} \Delta I

.

Taking the magnitude of the induced charge,

q = \dfrac{M}{R} |\Delta I|

.

Substituting the given values,

M = 6 \times 10^{-3}

H,

R = 6\ \Omega

, and

|\Delta I| = |2 - 7| = 5

A.

q = \dfrac{6 \times 10^{-3}}{6} \times 5 = 5 \times 10^{-3}

C

= 5

mC.

Answer:

5

mC

The value of mutual inductance of two coils is 6 mH. The current in...

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