Two identical inductors are connected in parallel. If the parallel combination stores 40 J of magnetic field energy when a total current of 2 A is passed through it, the value of the self-inductance of each coil is

Step-by-step solution

Let the self-inductance of each coil be L . Since the two identical inductors are connected in parallel, their equivalent inductance L_ eq is given by: L_ eq = L 2 The magnetic potential energy stored in the equivalent inductor is: U = 1 2 L_ eq I^2 Given U = 40 J and total current I = 2 A , substituting these values: 40 = 1 2 ( L 2 ) (2)^2 40 = L 4 4 L = 40 H Answer: 40 H