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MHT CET 202625 AprilEvening Shift
Exam
MHT CET
Year
2026
Date
25 April
Shift
Evening Shift
Subject
Physics
Chapter
Electromagnetic Induction

MHT CET 2026 · 25 April · Evening Shift · Physics · Electromagnetic Induction

The coefficient of coupling is 0.8 . If the mutual inductance is 8\...

The coefficient of coupling is 0.80.8. If the mutual inductance is 8 H8\ \text{H}, then the values of self-inductances L1L_1 and L2L_2 of the coil are

Options

  1. A60 H60\ \text{H} and 40 H40\ \text{H}
  2. B90 H90\ \text{H} and 10 H10\ \text{H}
  3. C5 H5\ \text{H} and 20 H20\ \text{H}
  4. D5 H5\ \text{H} and 10 H10\ \text{H}

Correct answer

C. 5 H5\ \text{H} and 20 H20\ \text{H}

Step-by-step solution

The relation between mutual inductance MM, self-inductances L1L_1 and L2L_2, and the coefficient of coupling kk is given by

M=kL1L2M = k \sqrt{L_1 L_2}

Substituting the given values M=8 HM = 8\ \text{H} and k=0.8k = 0.8, we get

8=0.8L1L28 = 0.8 \sqrt{L_1 L_2}

L1L2=80.8=10\sqrt{L_1 L_2} = \dfrac{8}{0.8} = 10

Squaring both sides, we obtain

L1L2=100L_1 L_2 = 100

Checking the given options, the product of 5 H5\ \text{H} and 20 H20\ \text{H} is 100100.

Therefore, the values of self-inductances are 5 H5\ \text{H} and 20 H20\ \text{H}.

Answer: 5 H5\ \text{H} and 20 H20\ \text{H}
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