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MHT CET Medical202624 April 2026Evening ShiftPhysicsElectromagnetic InductionActual

A wire of length 1 m is moving at a speed of 2 m/s perpendicular to its length in a homogeneous magnetic field of 0.5 T . If the ends of the wire are joined to a circuit of resistance 6 , then the rate at which work is being done to keep the wire moving at constant speed is

Options

  1. A1 W
  2. B1 3 W
  3. C1 6 W
  4. D1 12 W

Correct answer

C. 1 6 W

Step-by-step solution

The motional emf induced in the wire is given by e = Bvl Substituting the given values, we get e = 0.5 2 1 = 1 V The rate at which work is done to keep the wire moving at a constant speed is equal to the electrical power dissipated in the circuit. P = e^2 R P = 1^2 6 = 1 6 W Answer: 1 6 W

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