NEETPhysicsElectromagnetic Induction
The diagram below shows two circle loops of wire (A and B) centred on and perpendicular to the x -axis, and oriented with their planes parallel to each other. The y -axis passes vertically through loop A (dashed line). There is a current I_ B in loop B as shown. Possible actions which we might perform on loop A are: (i) Move A to the right along x axis closer to B (ii) Move A to the left along x axis away from B (iii
Options
- AOnly (i)
- BOnly (ii)
- COnly (i) and (iv)
- DOnly (ii) and (iii)
Correct answer
A. Only (i)
Step-by-step solution
When we move loop A to the right, closer to loop B, the magnetic flux through loop A increases. According to Lenz's Law, the induced current will create a magnetic field to oppose this increase. Since loop B's current ( (I_B )) creates a magnetic field that points to the right (inside the loop) based on the right-hand rule, the induced current in loop A must create a magnetic field pointing to the left to oppose it. For loop A to create a magnetic field pointing to the left, the induced current must flow in the dir