In the figure shown, q is in coulomb and t in second. At time ( t= 1 ~s ) (a) ( V_ a -V_ b = 4 ~V ) (b) ( V_ b -V_ c = 1 ~V ) (c) ( V_ c -V_ d = 16 ~V ) (d) ( V_ a -V_ d = 20 ~V )

Correct answer: C. (a), (b) and (c) are correct aligned & q=2 t^2 & i=(d q)/(d t)=4 t & (d i)/(d t)=4 A / s s & At t=1 s, q=2 C, i=4 A & and (d i)/(d t)=4 A / s & V_a-V_b=L (d i)/(d t)=1 × 4=4 V & V_b-V_c=(q)/(C)=(2)/(2)=1 V & V_C-V_d=i r=4 × 4=16 V & V_a-V_d is summation of above three i.e. 21 V . aligned )

NEET

Exam: NEET
Subject: Physics
Chapter: Electromagnetic Induction

NEET · Physics · Electromagnetic Induction

In the figure shown, q is in coulomb and t in second. At time ( t=...

In the figure shown, q is in coulomb and t in second. At time (

\mathrm{t}=

\mathrm{~s}

)

In the figure shown, q is in coulomb and t in second. At time ( t= 1 ~s ) (a) ( V_ a -V_ b = 4 ~V ) (b) ( V_ b -V_ c =

(a) (

\mathrm{V}_{\mathrm{a}}-\mathrm{V}_{\mathrm{b}}=

\mathrm{~V}

) (b) (

\mathrm{V}_{\mathrm{b}}-\mathrm{V}_{\mathrm{c}}=

\mathrm{~V}

) (c) (

\mathrm{V}_{\mathrm{c}}-\mathrm{V}_{\mathrm{d}}=

\mathrm{~V}

) (d) (

\mathrm{V}_{\mathrm{a}}-\mathrm{V}_{\mathrm{d}}=

\mathrm{~V}

)

Options

Aonly (a) is correct
Bonly (b) is correct
C(a), (b) and (c) are correct
Donly (d) is correct

Correct answer

C. (a), (b) and (c) are correct

Step-by-step solution

\begin{aligned} & q=2 t^2 \\ & i=\frac{d q}{d t}=4 t \\ & \frac{d i}{d t}=4 A / s \mathrm{ s} \\ & \text{At } t=1 s, q=2 C, i=4 A \\ & \text{and } \frac{d i}{d t}=4 A / s \\ & V_a-V_b=L \frac{d i}{d t}=1 \times 4=4 V \\ & V_b-V_c=\frac{q}{C}=\frac{2}{2}=1 V \\ & V_C-V_d=i r=4 \times 4=16 V \\ & V_a-V_d \text{ is summation of above three i.e. } 21 V \text{. }\end{aligned}

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