NEETPhysicsElectromagnetic Induction
A rectangular coil of 100 turns, having dimensions 25 cm 20 cm , is rotated in a uniform magnetic field of 0.2 T . The electrical resistance of the coil is 20 . If the maximum induced current in the coil is 3.14 A , what is the frequency of rotation of the coil in revolutions per minute (rpm)? (Take = 3.14 )
Options
- A600 rpm
- B10 rpm
- C300 rpm
- D1200 rpm
Correct answer
A. 600 rpm
Step-by-step solution
The area of the rectangular coil is A = 25 cm 20 cm = 0.25 m 0.20 m = 0.05 m ^2 . The maximum induced EMF in a rotating coil is given by _ max = NAB , where = 2 f . The maximum induced current is I_ max = _ max R = NAB(2 f) R . Substituting the given values: 3.14 = 100 0.05 0.2 2 3.14 f 20 3.14 = 1 6.28 f 20 f = 3.14 20 6.28 = 10 Hz . To convert the frequency to revolutions per minute (rpm), multiply by 60 : Frequency in rpm = 10 60 = 600 rpm . Answer: 600 rpm