AIIMS2019PhysicsElectromagnetic Induction
For a toroid N=500 , radius =40 ~cm , and area of cross section =10 ~cm ^2 . Find inductance.
Options
- A125 H
- B250 H
- C0.00248 H
- Dzero
Correct answer
A. 125 H
Step-by-step solution
If we flow a current i , then aligned & _ self =(B A) N= ( ₀ N i 2 R ) A N & _ self = ( ₀ N^2 A 2 R ) i and _ self =L i aligned aligned & L= ₀ N^2 A 2 R = ₀ 4 2 N^2 A R & L= (10⁻⁷ ) 2 (500)^2 10 (10⁻² )^2 0.4 &=125 H aligned