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AIIMS 201826 May

Exam: AIIMS
Year: 2018
Date: 26 May
Subject: Physics
Chapter: Electromagnetic Induction

AIIMS 2018 · 26 May · Physics · Electromagnetic Induction

A circular ring of diameter 20 ~cm has a resistance of 0.01 . The...

A circular ring of diameter

20 \mathrm{~cm}

has a resistance of

0.01 \Omega

. The charge that will flow through the ring if it is turned from a position perpendicular to a uniform magnetic field of

2.0 \mathrm{~T}

to a position parallel to the field is about

Options

A $63 \mathrm{C}$
B $0.63 C$
C $6.3 \mathrm{C}$
D $0.063 \mathrm{C}$

Correct answer

C. $6.3 \mathrm{C}$

Step-by-step solution

As

\begin{aligned} q & =\frac{-d \phi}{R}=\frac{B A\left(\cos 0^{\circ}-\cos 90^{\circ}\right)}{R} \\ & =\frac{B \pi r^2(1-0)}{R}=\frac{B \pi r^2}{R} \\ & =\frac{2 \times 3.14 \times\left(10^{-1}\right)^2}{0.01} \\ & =6.28 \mathrm{C} \simeq 6.3 \mathrm{C}\end{aligned}

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