A small piece of metal wire is dragged across the gap between the pole pieces of a magnet in 0.4 sec . If magnetic flux between the pole pieces is known to be 8 × 10^ -4 ~Wb , then induced emf in the wire, is

Correct answer: C. 2 × 10^ -3 ~V The charge of flux through the metal wire Time taken aligned Δ φ & =8 × 10^ -4 ~Wb Δ t & =0.4 sec aligned Induced emf. aligned e & =(Δ φ)/(Δ t) & = 8 × 10^ -4 0.4 & =20 × 10^ -3 ~V aligned

AIIMS 2001

Exam: AIIMS
Year: 2001
Subject: Physics
Chapter: Electromagnetic Induction

AIIMS 2001 · Physics · Electromagnetic Induction

A small piece of metal wire is dragged across the gap between the...

A small piece of metal wire is dragged across the gap between the pole pieces of a magnet in

0.4 \mathrm{sec}

. If magnetic flux between the pole pieces is known to be

8 \times 10^{-4} \mathrm{~Wb}

, then induced emf in the wire, is

Options

A $4 \times 10^{-3} \mathrm{~V}$
B $8 \times 10^{-3} \mathrm{~V}$
C $2 \times 10^{-3} \mathrm{~V}$
D $6 \times 10^{-3} \mathrm{~V}$ .

Correct answer

C. $2 \times 10^{-3} \mathrm{~V}$

Step-by-step solution

The charge of flux through the metal wire Time taken \begin{aligned} \Delta \phi & =8 \times 10^{-4} \mathrm{~Wb} \\ \Delta t & =0.4 \mathrm{sec} \end{aligned}

\therefore

Induced emf. \begin{aligned} e & =\frac{\Delta \phi}{\Delta t} \\ & =\frac{8 \times 10^{-4}}{0.4} \\ & =20 \times 10^{-3} \mathrm{~V} \end{aligned}

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