BITSAT 2016
- Exam
- BITSAT
- Year
- 2016
- Subject
- Mathematics
- Chapter
- Complex Number
BITSAT 2016 · Mathematics · Complex Number
If z_ 1 = 3 +i 3 and z_ 2 = 3 +i , then the complex number ( z_ 1...
If and , then the
complex number lies in the :
Options
- Afirst quadrant
- Bsecond quadrant
- Cthird quadrant
- Dfourth quadrant
Correct answer
A. first quadrant
Step-by-step solution
\left[\left(\frac{\sqrt{3}(1+i)}{\sqrt{3}+i}\right)^{2}\right]^{25}=\left[\frac{3(2 i)}{3-1+2 \sqrt{3} i}\right]^{25}=\left(\frac{3 i}{1+\sqrt{3} i}\right)^{25}=\frac{3^{25} i^{25}}{\left(-2 \omega^{2}\right)^{25}}
lies in the first quadrant as both real and imaginary parts of this number are positive.